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If m1,m2 are the slopes of the two tange...

If `m_1,m_2` are the slopes of the two tangents that are drawn from (2,3) to the parabola `y^2=4x` , then the value of `1/m_1+1/m_2` is

A

-3

B

3

C

`2/3`

D

`3/2`

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The correct Answer is:
To solve the problem of finding the value of \( \frac{1}{m_1} + \frac{1}{m_2} \) for the slopes \( m_1 \) and \( m_2 \) of the tangents drawn from the point (2,3) to the parabola \( y^2 = 4x \), we can follow these steps: ### Step 1: Identify the equation of the parabola The given parabola is \( y^2 = 4x \). This is a standard form of a parabola that opens to the right. ### Step 2: Write the equation of the tangent For a parabola of the form \( y^2 = 4ax \), the equation of the tangent at a point with slope \( m \) is given by: \[ y = mx + \frac{a}{m} \] Here, \( a = 1 \) (since \( 4a = 4 \)), so the equation of the tangent becomes: \[ y = mx + \frac{1}{m} \] ### Step 3: Substitute the point (2,3) into the tangent equation Since the tangents pass through the point (2,3), we substitute \( x = 2 \) and \( y = 3 \) into the tangent equation: \[ 3 = 2m + \frac{1}{m} \] ### Step 4: Multiply through by \( m \) to eliminate the fraction To eliminate the fraction, multiply the entire equation by \( m \): \[ 3m = 2m^2 + 1 \] ### Step 5: Rearrange the equation Rearranging gives us a standard quadratic equation: \[ 2m^2 - 3m + 1 = 0 \] ### Step 6: Solve the quadratic equation for \( m \) We can use the quadratic formula \( m = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 2 \), \( b = -3 \), and \( c = 1 \): \[ m = \frac{3 \pm \sqrt{(-3)^2 - 4 \cdot 2 \cdot 1}}{2 \cdot 2} \] \[ m = \frac{3 \pm \sqrt{9 - 8}}{4} \] \[ m = \frac{3 \pm 1}{4} \] This gives us two solutions: \[ m_1 = \frac{4}{4} = 1 \quad \text{and} \quad m_2 = \frac{2}{4} = \frac{1}{2} \] ### Step 7: Calculate \( \frac{1}{m_1} + \frac{1}{m_2} \) Now, we compute \( \frac{1}{m_1} + \frac{1}{m_2} \): \[ \frac{1}{m_1} + \frac{1}{m_2} = \frac{1}{1} + \frac{1}{\frac{1}{2}} = 1 + 2 = 3 \] ### Final Answer Thus, the value of \( \frac{1}{m_1} + \frac{1}{m_2} \) is \( \boxed{3} \).
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ARIHANT MATHS-PARABOLA-Exercise For Session 2
  1. The normals at three points P,Q,R of the parabola y^2=4ax meet in (h,k...

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  2. The set of points on the axis of the parabola y^2-4x-2y+5=0 from which...

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  3. Prove that any three tangents to a parabola whose slopes are in harmon...

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  4. prove that the locus of the point of intersection of the tangents at t...

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  5. Find the equation of the normal to the parabola y^2=4x which is para...

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  6. Find the equation of the normal to the parabola y^2=4x which is perp...

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  7. The ordinates of points P and Q on the parabola y^2=12x are in the rat...

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  8. The normals at P, Q, R on the parabola y^2 = 4ax meet in a point on th...

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  9. The normals are drawn from (2lamda,0) to the parabola y^2=4x .Show tha...

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  10. If m1,m2 are the slopes of the two tangents that are drawn from (2,3) ...

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  11. The angle between the tangents drawn from the origin to the parabola y...

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  12. IF (a,b) is the mid point of chord passing through the vertex of the p...

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  13. The diameter of the parabola y^2=6x corresponding to the system of par...

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  14. Tangents are drawn from the point (-1, 2) to the parabola y^2 =4x The ...

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  15. for parabola x^2+y^2+2xy−6x−2y+3=0, the focus is (a) (1,-1) (b) (-1,1...

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  16. Find the locus of the mid-points of the chords of the parabola y^2=4ax...

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  17. A ray of light moving parallel to the X-axis gets reflected from a par...

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  18. The locus of the point of intersection of the tangents to the parabola...

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  19. The lacus of the middle points of the chords of the parabola y^(2)=4ax...

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  20. Tangents are drawn from the point (-1, 2) to the parabola y^2 =4x The ...

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