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If x=e^(-t^(2)), y=tan^(-1)(2t+1), then ...

If `x=e^(-t^(2)), y=tan^(-1)(2t+1)`, then `(dy)/(dx)=`

A

`(e^((t^2)))/((2t)(2t^2-2t+1))`

B

`(e^(-(t^2)))/((2t)(2t^2+2t+1))`

C

`-(e^(-(t^2)))/((2t)(2t^2-2t+1))`

D

`-(e^((t^2)))/((2t)(2t^2+2t+1))`

Text Solution

Verified by Experts

The correct Answer is:
D
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