In a DeltaABC, the median to the side BC...

In a `DeltaABC`, the median to the side BC is of length `1/sqrt(11-6sqrt3)` and it divides the `angleA` into angles `30^@` and `45@.` Find the length of the side BC.

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The correct Answer is:

`BC=2BD=(AD)/(sin B)=(2sqrt(11-6sqrt3))/(sqrt(11-6sqrt3))=2`

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