Home
Class 12
MATHS
If the base angles of triangle are (22)/...

If the base angles of triangle are `(22)/(12)a n d112 1/2^0` , then prove that the altitude of the triangle is equal to `1/2` of its base.

A

half the base

B

the base

C

twice the base

D

four times the base

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • PROPERTIES AND SOLUTION OF TRIANGLES

    ARIHANT MATHS|Exercise Exercise For Sesssion 3|33 Videos
  • PROPERTIES AND SOLUTION OF TRIANGLES

    ARIHANT MATHS|Exercise Exercise For Sesssion 4|8 Videos
  • PROPERTIES AND SOLUTION OF TRIANGLES

    ARIHANT MATHS|Exercise Exercise For Sesssion 1|20 Videos
  • PRODUCT OF VECTORS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|52 Videos
  • SEQUENCES AND SERIES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|38 Videos

Similar Questions

Explore conceptually related problems

If the base angles of triangle are ((22)/(12))^(@) and (112(1)/(2))^(@), then prove that the altitude of the triangle is equal to (1)/(2) of its base.

If the base angles of a triangle are 22(1)/(2),112(1)/(2) then third angle is

If the area of triangle with base 12 cm is equal to the area of a square with side 12 cm, then the altitude of the triangle is:

If the bisectors of the base angles of a triangle enclose an angle of 135^(0) ,prove that the triangle is a right triangle.

If the bisectors of the base angles of a triangle enclose an angle of 135^(0) ,prove that the triangle is a right triangle.

If the area of a triangle is 1176 cm^(2) and base : corresponding altitude is 3:4, then the altitude of the triangle is:

If the area of an isosceles triangle is sqrt(2)+1 and vertical angle is 45^(@) then the base of the triangle is

If the orthocenter of an isosceles triangle lies on the incircle of the triangle then A) the base angle of the triangle is cos^-1 2/3 B) the triangle is acute C) the base angle of the triangle is tan^-1 (sqrt5/2) D) If S, I are the circumcentre and incentre and R is circumradius then SI/R=1/3

ARIHANT MATHS-PROPERTIES AND SOLUTION OF TRIANGLES -Exercise For Sesssion 2
  1. If in a triangle ABC, (s-a)(s-b)= s(s-c), then angle C is equal to

    Text Solution

    |

  2. In any Delta ABC, If cot ""A/2 , cot ""B/2 ,cot ""C/2 are in AP, t...

    Text Solution

    |

  3. In any DeltaABC,("tan"(A)/(2)-"tan"(B)/(2))/("tan"(A)/(2)+"tan"(B)/(2)...

    Text Solution

    |

  4. In a triangle ABC, bc co s^2 A/2 + ca co s^2 B/2 + ab co s ^2C/2 =

    Text Solution

    |

  5. In a Delta ABC, if cos A+cos C=4 sin^(2)((B)/(2)), then a,b,c are in

    Text Solution

    |

  6. In a triangle ABC, if b^2 + c^2 = 3a^2, then cotB + cotC-cotA is equal...

    Text Solution

    |

  7. In any Delta ABC, ((b-c)/(a))cos^(2)((A)/(2))+((c-a)/(b))cos ^(2)((b )...

    Text Solution

    |

  8. If in a DeltaABC, the tangent of half the difference of two angles is ...

    Text Solution

    |

  9. If in a triangle a cos^2C/2+cos^2A/2=(3b)/2, then find the relation be...

    Text Solution

    |

  10. If c^(2)=a^(2) +b^(2), then 4s(s-a)(s-b)(s-c) is equal to

    Text Solution

    |

  11. The number of possible angle ABC in which BC =sqrt11cm, CA=sqrt13cm an...

    Text Solution

    |

  12. If two sides a, b and the angle A be such that the sum of two values o...

    Text Solution

    |

  13. If in a DeltaABC, sin A =sin^(2) B and 2 cos ^(2)A=3 cos ^(2) B, then ...

    Text Solution

    |

  14. If a cos A =b cos B, then the triange is

    Text Solution

    |

  15. Point D,E are taken on the side BC of an acute angled triangle ABC,, s...

    Text Solution

    |

  16. If the base angles of triangle are (22)/(12)a n d112 1/2^0 , then prov...

    Text Solution

    |

  17. In a DeltaABC, a =1 and the perrimeter is six times the AM of the sinc...

    Text Solution

    |

  18. In a DeltaABC, if median AD is perpendicular to AB, the tan A+2 tan B ...

    Text Solution

    |

  19. The product of the sines of the angles of a triangle is p and the pro...

    Text Solution

    |