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If H is the orthocentre of the triangle ...

If H is the orthocentre of the triangle ABC, R = circumradius and `P =AH +BH+CH,` then

A

`p=2 (R+r)`

B

max, of P is 3R

C

min. of P is 3R

D

`P=2 (R-r)`

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The correct Answer is:
A, B
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