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ABCD is a trapezium such that `AB and CD` are parallel and `BC _|_ CD`. If /_ADB= theta , BC =p and CD=q`, then AB is equal to

A

`((p^(2)+q^(2))sin theta)/(p cos theta +q sin theta)`

B

`(p ^(2) + q ^(2)cos theta)/(p cos theta +q sin theta)`

C

`(p ^(2)+ q^(2))/(p^(2)cos theta +q^(2) sin theta)`

D

`((p^(2) +q^(2))sin theta)/((p cos theta + sin theta)^(2))`

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The correct Answer is:
A
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