The human body contains `18%` carbon by weight, in which `.^(14)C` is `1.56xx10^(-6)` per cent. If the half-life of `.^(14)C` is `5570` year, then the number of disintengration per mintute in the body of this weight is:

Options

A. `194`
B. `1940`
C. `19400`
D. `28600`

Answer

`(d)`

Explanation

Amount of `.^(14)C` in body
`= (18 xx w xx 1.56xx10^(-10)xx6.023xx10^(23))/(100xx100xx14)`
(where `w` is `wt`. Of body)
`:.` rate `= lambda xx` No. of atoms
`= (0.693)/(5570xx365xx24xx60)`
`xx (18xx1.56xx10^(-10)xx6.023xx10^(23))/(100xx100xx14)w`
Rate/Body `wt. = 2.86xx10^(4)` dpm