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Half-life on an element is 't' secound. ...

Half-life on an element is `'t'` secound. In `t//2` second the fraction of the element decayed is:

A

`29%`

B

`25%`

C

`21%`

D

`17%`

Text Solution

Verified by Experts

The correct Answer is:
`(a)`
`(t)/(2) = (2.303xx t_(1//2))/(0.693) log (N_(0))/(N) (t_(1//2) = t)`
Find `N` putting `N_(0) = 100`, then calculate amount decayed `= 100-N`
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