In the nuclear chain ractio:
`._(92)^(235)U + ._(0)^(1)n rarr ._(56)^(141) Ba + ._(36)^(92)Kr + 3 ._(0)^(1)n + E`
The number fo neutrons and energy relaesed in nth step is:

Options

A. `3n, nE`
B. `3^(n), nE`
C. `3^(n), 3^(n-1) E`
D. none of these

Answer

`(c)`

Explanation

In `n^(th)` step neutrons ejected will be `3^(n)` and energy `3^(n-1)E` because one step ejects 3 electrons and energy `E.e.g` consider `II` step. In `2nd` step a neutrons `(3^(2))` and `3E` energy `(3^(2-1)E)` is liberated.