Two radioactive nuclides `A` and `B` have half-lives in the ratio `2:3` respectively. An experiment is made with one mole of each of them. Calculate the molar ratio of `A` and `B` after a time interval of three times of half-line of `A`.

Options

A. `1:2`
B. `2:1`
C. `1:3`
D. `3:1`

Answer

`(a)`

Explanation

Half-life of `A` si `2a` and half-line of `B` si `3a`
For `A: 6a = (2.303xx2a)/(0.693) log ((1)/(n_(A)))`
For `B: 6a = (2.303xx3a)/(0.693) log ((1)/(n_(g)))`
`:. N_(A) = 0.125`
`N_(B) = 0.250`
`:. (N_(A))/(N_(B)) = 1:2`