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The deacy time t for radioactive element...

The deacy time `t` for radioactive element proceeds to `4` half-lives. The total decay time `(t)` in terms of average life `(T)` is given by:

A

`t = 27` In `2`

B

`t = 4T` In `2`

C

`t = 27^(4)` In `2`

D

`(1)/(T^(2))` In `2`

Text Solution

Verified by Experts

The correct Answer is:
`(b)`

`t = 4xx t_(1//2)`
Also `t_(1//2) = (0.693)/(lambda) = 0.693xx T`
`:. t = 4xx0.693xx T`
`= 4T` in `2`
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