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A radioactive species undergoes decay fo...

A radioactive species undergoes decay for time `t` where `t = 4t_(1//2)` . The average life `(T)` of species can therefore be given by:

A

`2t` in `2 = T`

B

`4t` in `2 = T`

C

`T = (t)/(4 "In" 2)`

D

`T = (t)/(2 "In" 2)`

Text Solution

Verified by Experts

The correct Answer is:
`(c)`
`T = (1)/(lambda) = (t_(1//2))/(0.693) = (t)/(4xx0.693) = (t)/(4 "in" 2)`
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