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The half-life of a radioisotoe is four h...

The half-life of a radioisotoe is four horu. If the initial mass of the isotope was `200g`, the mass left after 24 hour undercayed is:

A

`4.167g`

B

`2.084g`

C

`3.125g`

D

`1.042g`

Text Solution

Verified by Experts

The correct Answer is:
`(c)`
`N_("Left") = (N_(0))/(2^(n)) = (200)/(2^(6)) = 3.125g`
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