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.(13)Al^(27) is a stable isotope. .(13)A...

`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by

A

`alpha-` emission

B

`beta-` emission

C

postion emission

D

proton emission

Text Solution

Verified by Experts

The correct Answer is:
`(b)`
Nuclides having `(n)/(p) gt 1` undergoes `beta-` emission to decreases `(n)/(p)` in order to attain belt of stablitly i.e.,
`(n)/(p) = 1`
`._(13)^(29)Al rarr ._(14)^(29)Si + ._(-1)e^(0)`
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