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.^(23) Na is the more stable isotope of ...

`.^(23)` Na is the more stable isotope of Na. Find out the process by which `._(11)^(24)` Na can undergo radioactive decay.

A

`beta-` emssion

B

`alpha-` emission

C

`beta^(+)` -emission

D

`K-` electron capture

Text Solution

Verified by Experts

The correct Answer is:
`(a)`
`._(1q)^(23) Na: (n)/(p) = (12)/(11)`
`._(11)^(24) Na: (n)/(p) = (13)/(11)` , `( :' (n)/(p) gt 1)`
Decreases in `n//p` ratio gives out `beta-` particles
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