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Statement: .(26)^(56)Fe is most stable ...

Statement: `._(26)^(56)Fe` is most stable nucleus.
Explanation: Binding energy per nucleon is maximum for `._(926)^(56)Fe`

A

`S` is correct but `E` is wrong.

B

`S` is wrong but `E` is correct.

C

Both `S` and `E` are correct and `E` is correct explanation of `S`.

D

Both `S` and `E` are correct but `E` is not correct explanation of `S`.

Text Solution

Verified by Experts

The correct Answer is:
`c`
The binding energy per nucleons increases upto `._(926)Fe` and becomes maximum at `8.7 MeV`. It then decreases. More is binding energy, lesser is energy level of nucleus more is its stabliltiy.
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Knowledge Check

  • The value of binding energy per nucleon is

    A
    more for light nuclei
    B
    more for heavy nuclei
    C
    more for medium nuclei
    D
    equal for all nuclei

  • The binding energy per nucleon is maximum in the case of.

    A
    `._2^4 He`
    B
    `._26^56 Fe`
    C
    `._56^141 Ba`
    D
    `._92^235 U`

  • The average binding energy per nucleon is maximum for the nucleus

    A
    `""_(2)He^(4)`
    B
    `""_(8)O^(16)`
    C
    `""_(26)Fe^(36)`
    D
    `""_(92)U^(238)`

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