Determine the ox.no. of underlined atom in each of the following:
(a) `Kul(Cr)O_(3)Cl`, (b) `K_(2)ul(Fe)O_(4)`,
(c ) `Ba(H_(2)ul(P)O_(2))_(2)` (d) `Rb_(4)Na[Hul(V)_(10)O_(28)]`
(e ) `Ba_(2)ul(Xe)O_(6)`
(f) `Na_(2)ul(S)_(2)`
(g) `K_(2)ul(Mn)O_(4)` (h) `K_(2)ul(Cr)_(2)O_(7)`
(i) `ul(Mn)O_(4)^(-)`
(j) `ul(S)O_(4)^(2-)`
(k) `ul(P)O_(4)^(3-)`
(I) `ul(C )O_(3)^(2-)`
(m) `ul(Cu)(NH_(3))_(4)^(2+)` (n) `ul(Ni)(CO)_(4)`
(o) `ul(C )s_(2)` (p) `(NH_(4))_(6)ul(Mo)_(7)O_(24)`
(q) `[ul(Co)F_(4)]^(-)` (r) `ul(Os)O_(4)`
(s) `Na_(4)ul(Xe)O_(6)` (t) `Kul(Cr)O_(3)Cl`
(u) `ul(F)_(2)H_(2)`

Explanation

(a) Let ox. no. of `Cr` be `'a'`, then
`1+a + 3 xx (-2)+1 xx (-1) = 0 rArr a=+6`
(b) `2 xx 1+a+4 xx (-2) = 0 rArr a=+6`
(c ) `2+2[2xx1+a+2xx(-2)] = 0 rArr a = +1`
(d) `4 xx 1+1+[1+10 xx a + 28 xx (-2)] = 0 rArr a=+5`
(e) `2 xx 2 + a + 6 xx (-2) = 0 rArr a=+8`
(f) `1xx2+2xxa=0 rArr a=-1`
(g) `2xx1+a+4xx(-2) = 0 rArr a = +6`
(h) `2 xx 1 + 2 xx s + 7 xx (-2) = 0 rArr a = + 6`
(i) `a + 4 xx (-2) =-2 rArr a = +7`
(j) `a+4 xx (-2) = -2 rArr a = +6`
(k) `a+4 xx (-2) = -3 rArr a = +5`
(l) `a+3 xx (-2) = -2 rArr a = +4`
(m) `a + 4 xx 0 = +2 rArr a = +2`
(n) `a + 4 xx 0 = 0 rArr a = 0`
(o) `a + 2 xx (-2) = 0 rArr a = +4`
(p) `1 xx 6 + 7 xx a + 24 xx (-2) = 0 rArr a = +6`
(q) `a + 4 xx (-1) = -1 rArr a = +3`
(r ) `a + 4 xx (-2) = 0 rArr a = +8`
(s) `4 xx 1 + a + 6 xx (-2) = 0 rArr a = +8`
(t) `1 + a + 3 xx (-2) + 1(-1) = 0 rArr a = +6`
(u) `2 xx a + 2 xx (1) = 0 rArr a = -1`