In a reaction, `Cr_(2)O_(7)^(2-)` is reduced to `Cr^(3+)`. What is concentration of `0.1M K_(2)Cr_(2)O_(7)` in equivalent per litre?
`Cr_(2)O_(7)^(2-)+14H^(+)+6erarr2Cr^(3+)+7H_(2)O`

Explanation

`N = M xx " valence factor"`
`therefore N = 0.1 xx 6`
`(Cr_(2)^(6+) + 6erarr 2Cr_(3+))`
or `N_(K_(2)Cr_(2)O_(7)) = 0.6 N`