What mass of `K_(2)Cr_(2)O_(7)` is required to produce `5.0` litre `CO_(2) "at" 75^(@)C` and `1.07 atm` Pressure on treating with excess of `H_(2)C_(2)O_(4)` in acidic medium?

Explanation

`"mole of" CO_(2)=(PV)/(RT)=(1.07xx5)/(0.0821xx348)`
`=0.187`
`(C^(3+))_(2)rarr2C^(4+)+2e`
`6e+(Cr^(6+))_(2)rarr2Cr^(3+)`
Meq. Of `K_(2)Cr_(2)O_(7)=` Meq.of `H_(2)C_(2)O_(4)`
`=` Meq of `CO_(2)=` Mole of `CO_(2)xx1000`
(Valence factore of ` CO_(2)=1)`
`(W)/(E)xx1000=0.187xx1000`
`(w)/(M//6)xx1000=0.187xx1000`
`(M_(K_(2)Cr_(2)O_(7)=294.2))`
`W_(K_(2)Cr_(2)O_(7))=(0.187xx294.2)/(6)=9.17g`