What mass of `N_(2)H_(4)` can be oxidised to `N_(2)` by `24.0 g K_(2)CrO_(4)`, which is reduced to `Cr(OH)_(4)^(-)`?

Explanation

`N_(2)^(2-)rarrN_(2)^(0)+4e`
`Cr^(6+)=3erarrCr^(3+)`
Meq. Of `N_(2)H_(4)=Meq. Of K_(2)CrO_(4)`
`(w)/(32//4)xx1000=(24)/(194.2//3)xx1000`
`(Etwt.=(M.wt)/("Valence factor"))`
`w_(N_(2)H_(4)=2.97g`