Calculate the mass of oxalic acid `(H_(2)C_(2)O_(4))` which can be oxidised to `CO_(2)` by `100.0mL` of `MnO_(4)^(-)` solution, `10 mL` of which is capable of oxidising `50.0mL` of `1.0NI^(-)` to `I_(2)`?

Explanation

`Mn^(7+)+5erarrMn^(2+)`
`2I^(-)rarrI_(2)+2e`
Meq. Of `I^(-)=` Meq.of `MnO_(4)^(-)`
`50xx1.0=10xxN`
`N_(MnO_(4)^(-))=5`
Now `Mn^(7+)+5erarrMn^(2+)`
`C_(2)^(3+)rarr2C^(4+)+2e`
Meq.of `H_(2)C_(2)O_(4)=` meq.of `MnO_(4)^(-)`
`(w)/(90//2)xx1000=5xx100`
`w=22.5 g`