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A solution containing 1.984 g of crystal...

A solution containing `1.984 g` of crystalline `NA_(2)SO_(2)O_(3).xH_(2)O` in water required `40ml` of `N//5` lodine solution for complete reaction .Calculate the value of `x`

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`2S_(2)O_(3)^(2-)rarrS_(4)O_(6)^(2-)+2e`
`2e+I_(2)rarr2I^(-)`
Also Meq.of `I_(2)="Meq.of" Na_(2)S_(2)O_(3).xH_(2)O`
`40xx(1)/(2)=(1.984)/(M//1)xx1000`
`therefore M_(Na_(2)S_(2)O_(3).xH_(2)O)=248`
`2xx23+2xx32+16xx3+18x=248`
or `x=5`
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