The reaction of white phosphorus with aqueous `NaOH` gives phosphine along with another phosphorus containing compound. The reacation type, the oxidation states of phosphorus in phosphine and the other product are respectvely:

Options

A. redox reaction, `-3` and `-5`
B. redox reaction , `+3` and `+1`
C. disproportionation reaction, `-3` and `+1`
D. disproportionation reaction , `-3` and `+3`

Answer

C

Explanation

White phosphorus dissolved in `NaOH` on boiling in inert atmosphere.
`P_(4)+3NaOH+3H_(2)Orarrunderset(("Sodium hypophophite"))(3NaH_(2)PO_(2))+underset(("phosphine"))(PH_(3))`
Let the oxidation state of phosphorus be `a`.
`:.` In `PH_(3)rArra+3=0rArra=-3`
In `NaH_(2)PO_(2)`,
`+1+2(+1)+a+2(-2)=0`
`+3+a-4=0rArra=+1`