Home
Class 11
CHEMISTRY
Thermochemical equation for two rocket f...

Thermochemical equation for two rocket fuels are given below `:`
`2Al_((s))+(3//2)O_(2(g))rarr Al_(2)O_(3(s)),DeltaH=-1667.8kJ`
`H_(2(g))+1//2O_(2) rarr H_(2)O_((l)),DeltaH=-285.9kJ`

Text Solution

Verified by Experts

Calorific value of `Al=(-1667.8)/(54)=-30.88kJ //g`
Calorific value of `H_(2)=(-285.9)/(2)=-142.95kJ //g`
Thus `H_(2)` is better rocket fuel.
Promotional Banner

Topper's Solved these Questions

  • THERMOCHEMISTRY

    P BAHADUR|Exercise Exercise 2|1 Videos
  • THERMOCHEMISTRY

    P BAHADUR|Exercise Exercise 3|1 Videos
  • THERMOCHEMISTRY

    P BAHADUR|Exercise Hess Law|4 Videos
  • REDOX REACTIONS

    P BAHADUR|Exercise Exercise(8) Statement:Explanation type problems|19 Videos
  • THERMODYNAMICS

    P BAHADUR|Exercise Exercise|232 Videos

Similar Questions

Explore conceptually related problems

The thermochemical equation for solid and liquid rocket fuel are given below: 2AI(s) +1(1)/(2)O_(2)(g) rarr AI_(2)O_(3)(s), DeltaH =- 1667.8 kJ H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH =- 285.9 kJ a. If equal masses of aluminium and hydrogen are used, which is a better rocket fuel? b. Determine DeltaH for the reaction AI_(2)O_(3)(s) rarr 2AI(s)+1(1)/(2)O_(2)(g)

H_(2)(g)+(1)/(2)O_(2)(g)rarr2H_(2)O(l), DeltaH =- 286 kJ 2H_(2)(g)+O_(2)(g)rarr2H_(2)O(l)……………kJ(+-?)

Calculate the standard enthalpy of formation of acetylene from the following data : C_((g))+O_(2(g))rarr CO_(2(g)),DeltaH^(@)=-393kJ mol^(-1) H_(2(g))+(1)/(2)O_(2(g)) rarr H_(2)O_((l)),DeltaH^(@)=-285.8kJ mol^(-1) 2C_(2)H_(2(g))+5O_(2(g))rarr 4CO_(2(g))+2H_(2)O_((l)),DeltaH^(@)=-2598.8kJ mol^(-1) .

The enthalpy changes for two reactions are given by the equations: 2Cr(s) +(3)/(2)O_(2)(g) rarr Cr_(2)O_(3)(s), DeltaH^(Theta) =- 1130 kJ C(s) +(1)/(2)O_(2)(g)rarr CO_(2)(g), DeltaH^(Theta) =- 110 kJ What is the enthalpy change in kJ for the following reactions? 3C(s) +Cr_(2)O_(3)(s) rarr 2Cr(s) +3CO(g)

Calculate the heat of combustion of benzene form the following data: a. 6C(s) +3H_(2)(g) rarr C_(6)H_(6)(l), DeltaH = 49.0 kJ b. H_(2)(g) +1//2O_(2)(g) rarr H_(2)O(l), DeltaH =- 285.8 kJ c. C(s) +O_(2) (g) rarr CO_(2)(g), DeltaH =- 389.3 kJ