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The temperature of a 5mL of strong acid ...

The temperature of a `5mL` of strong acid increases by `5^(@)` when` 5 mL` of strong base is added to it . If `10mL` of each are mixed, temperature should increase by `:`

A

`5^(@)C`

B

`10^(@)C`

C

`15^(@)C`

D

cannot be know

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The correct Answer is:
To solve the problem step-by-step, we need to analyze the relationship between the volume of the acid and base, the heat of neutralization, and the resulting temperature change. ### Step 1: Understand the initial condition We have 5 mL of a strong acid and 5 mL of a strong base. When these two are mixed, the temperature increases by 5°C due to the heat released during the neutralization reaction. **Hint:** Remember that the temperature change (ΔT) is a result of the heat released during the reaction. ### Step 2: Define the heat of neutralization Let’s denote the heat of neutralization as Q. The heat released during the neutralization reaction is proportional to the amount of acid and base mixed, as well as the temperature change observed. **Hint:** Think about how heat (Q) is related to mass (m) and temperature change (ΔT) in the formula: Q = m * c * ΔT, where c is the specific heat capacity. ### Step 3: Analyze the change when volume is doubled If we double the volumes of both the acid and the base (from 5 mL to 10 mL), we are effectively doubling the amount of reactants. Since the heat of neutralization (Q) is proportional to the amount of reactants, we can say that the new heat of neutralization will be 2Q. **Hint:** Consider how the amount of reactants influences the total heat released in the reaction. ### Step 4: Relate the heat of neutralization to temperature change Since the heat (Q) is also proportional to the temperature change (ΔT), if we increase the heat of neutralization to 2Q, we need to consider how this affects the temperature change. However, since we are also doubling the mass (because we have more solution), the temperature change will not necessarily double. The temperature change will remain the same because the increased heat is distributed over a larger mass. **Hint:** Think about how temperature change is affected by both the amount of heat released and the mass of the solution. ### Step 5: Conclusion Thus, when we mix 10 mL of strong acid with 10 mL of strong base, the temperature increase will still be 5°C, the same as when we mixed 5 mL of each. **Final Answer:** The temperature should increase by 5°C. ---

To solve the problem step-by-step, we need to analyze the relationship between the volume of the acid and base, the heat of neutralization, and the resulting temperature change. ### Step 1: Understand the initial condition We have 5 mL of a strong acid and 5 mL of a strong base. When these two are mixed, the temperature increases by 5°C due to the heat released during the neutralization reaction. **Hint:** Remember that the temperature change (ΔT) is a result of the heat released during the reaction. ### Step 2: Define the heat of neutralization ...
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