A person requires `2870kcal` of energy to lead normal daily life. If heat of combustion of cane sugar is `-1349kcal`, then his daily comsumption of sugar is `:`

Options

A. `728g`
B. `0.728 g`
C. `342g`
D. `0.342g`

Explanation

To solve the problem, we need to determine how much cane sugar a person needs to consume daily to meet their energy requirement of 2870 kcal, given that the heat of combustion of cane sugar is -1349 kcal per mole.

### Step-by-Step Solution:

1. **Identify the Energy Requirement**:
The person requires 2870 kcal of energy per day.

2. **Identify the Energy from Cane Sugar**:
The heat of combustion of cane sugar is -1349 kcal per mole. This means that burning one mole of cane sugar releases 1349 kcal of energy.

3. **Calculate the Number of Moles of Cane Sugar Required**:
To find out how many moles of cane sugar are needed to meet the daily energy requirement, we can use the formula:
\[ \text{Number of moles} = \frac{\text{Energy required}}{\text{Energy per mole of sugar}} = \frac{2870 \text{ kcal}}{1349 \text{ kcal/mole}} \]
Performing the calculation:
\[ \text{Number of moles} = \frac{2870}{1349} \approx 2.13 \text{ moles} \]

4. **Calculate the Mass of Cane Sugar Required**:
Next, we need to convert the number of moles of cane sugar into grams. The molecular weight of cane sugar (sucrose) is approximately 342 g/mol. Thus, we can calculate the mass required:
\[ \text{Mass} = \text{Number of moles} \times \text{Molecular weight} = 2.13 \text{ moles} \times 342 \text{ g/mol} \]
Performing the calculation:
\[ \text{Mass} \approx 2.13 \times 342 \approx 727.26 \text{ grams} \]

5. **Conclusion**:
Therefore, the daily consumption of cane sugar required for the person to meet their energy needs is approximately **727.26 grams**.