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Bond energy of N-H,H-H and N-=N are a,b,...

Bond energy of `N-H,H-H` and `N-=N` are `a,b,c` respectively. The `DeltaH` for the reaction,
`2NH_(3) rarr N_(2)+3H_(2)` is `:`

A

`6a-3b-c`

B

`6a+3b+c`

C

`a+6b-c`

D

`6a+b-3c`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaH=` Bond energy data for dissociation `+` Bond energy data for formation
`=[2xxe_(N-H)xx3]+[-e_(N-=N)-3xxe_(H-H)]`
`=2xx3xxa+[-c-3xxb]=6a-c-3b`
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