`1 mol e` of ice melts at `0^(@)C` and constant pressure of `1 atm` by absorbing `1.44kcal ` heat . The density of ice `0.918 g//Ml` and of water `1g//mL` respectively. The two values of `DeltaH` and `DeltaU` differ by `:`

Options

A. `-0.039cal`
B. `+0.039cal`
C. `-0.39cal`
D. `+0.39cal`

Answer

A

Explanation

`{:(Ice,hArr,water,,),((18)/(0.918),,(18)/(1),,),(=19.6mL,,=18mL,,):}`
`:. DeltaV=18-19.6=-1.6mL`
Also`DeltaH-DeltaU=PDeltaV`
`=76xx13.6xx981xx(-1.6)erg`
`=-0.039 ( :' 4.18xx10^(7)erg=1 cal)`