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Calculate enthalpy change of the followi...

Calculate enthalpy change of the following reaction `:`
`H_(2)C=CH_(2(g))+H_(2(g)) rarr H_(3)C-CH_(3(g))`
The bond energy of `C-H,C-C,C=C,H-H` are `414,347,615` and `435k J mol^(-1)` respectively.

A

`+125kJ`

B

`-125kJ`

C

`+250kJ`

D

`-250kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH=-[e_(C-C)+6xxe_(C-H)]+[e_(C=C)+4xxe_(C-H)+e_(H-H)]`
`=-[347+6xx414]+[615+4xx414+435]`
`=-125kJ`
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