The enthalpies of combustion of carbon and carbond monoxide are `-393.5` and `-283kJ mol^(-1)` respectively . The enthalpy of formation of carbond monoxide per mole is `:`

Options

A. `-110.5kJ`
B. `676.5kJ`
C. `-676.5kJ`
D. `110.5kJ`

Answer

A

Explanation

`C+O_(2)rarr CO_(2),DeltaH=-393.5kJ`
`ul ( {: (CO,+(1)/(2)O_(2),rarrr,CO_(2),,DeltaH=-283kJ),(-,-,,-," +"):} )`
`C+(1)/(2)O_(2) rarr CO,DeltaH=-110.5kJ`