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Consider the reaction, N(2)+3H(2)hArr ...

Consider the reaction,
`N_(2)+3H_(2)hArr 2NH_(3)` carried out at constant pressure and temperature. If `DeltaH` and `DeltaU` are change in enthalpy and change in internal energy respectively, then `:`

A

`DeltaH=0`

B

`DeltaH=DeltaU`

C

`DeltaHltDeltaU`

D

`DeltaHgtDeltaU`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaH=DeltaU+DeltanRT`
`:.Deltan=2-4=-2`
`:. DeltaHltDeltaU`
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