The integral enthalpy of solution in `kJ` of one mole of `H_(2)SO_(4)` dissolved in `n` mole of water is given by `:`
`DeltaH_(s)=(75.6xxn)/(n+1.8)`
Calculate `DeltaH` for the following processes `:`
`(a)` 1 mole of `H_(2)SO_(4)` dissolved in 2 mole of `H_(2)O`.
`(b)` 1 mole of `H_(2)SO_(4)` dissolved in 7 mole of `H_(2)O`.
`(c )` 1 mole of `H_(2)SO_(4)` dissolved in 5 mole of `H_(2)O`.
`(d)` solution `(a)` dissolved in 5 mole of `H_(2)O`.
`(e)` 1 mole of `H_(2)SO_(4)` dissolved in excess of `H_(2)O`.

Answer

`(a) 39.79kJ, (b) 60.14kJ , (c ) 55.59kJ,`
`(d) 20.35kJ, (e) -75.60kJ;`