`1.0g` magnesium atoms in vapour phase absorbs `50.0kJ` of energy to convert all `Mg` into `Mg` ions. The energy absorbed is needed for the following changes `:`
`Mg_((g))rarr Mg_((g))^(+)+e, DeltaH=740kJ mol^(-1)`
`Mg_((g))^(+) rarr Mg_((g))^(2+)+e, DeltaH=1450kJ mol^(-1)`
Find out the `%` of `Mg^(+)` and `Mg^(2+)` in final mixture.

Answer

`Mg^(+)=68.28%,Mg^(2+)=31.72%`