The radius of `Cs^(+)` ion is `160pm` while the radius of `Cl^(-)` ion is `181pm`. Suggest the co`-`ordination of cesium in `CsCl`.
Text Solution
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Radius of `Cs^(+)=160 p m` Radius of `Cl^(-)=181 p m` Radius ratio `(r^(+))/(r^(-))=(160 p m)/(181p m)=0.884` The radius ratio is greater then `0.732` and therefore the co`-` ordination number of cesium in `CsCl` is 8.
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