The ratio of closed packed atoms to tetrahedral holes in cubic close packing is `:`
A
`1:1`
B
`1:2`
C
`1:3`
D
`2:1`
Text Solution
Verified by Experts
The correct Answer is:
b
Every constituent has two tetrahedral voids. In `c.c.p. ` lattice, atoms `=8xx(1)/(8)+6xx(1)/(2)=4` `:. ` Tetrahedral void `=4xx2=8` Thus ratio`=4:8::1:2`
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