The melting point of `RbBr` is `682^(@)C`, while that of `NaF` is `988^(@)C` . The principla reason that melting point of `NaF` is much higher than that of `RbBr` is that `:`
A
the two crystal are not isomorphous
B
the molar mass of `NaF` is smaller thean that of `RbBr`
C
the internuclear distance `r_(c)+r_(a)` is greater for `RbBr` than for `NaF`.
D
the bond in `RbBr` has more covalent character than the bond in `NaF`.
Text Solution
Verified by Experts
The correct Answer is:
c
This leads to stronger coulombic forces of attractions in `NaF`.
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