A solide `A^(+)B^(-)` has the `B^(-)` ions arranged as below. If the `A^(+)` ions occupy half of the tetrahedral sites in the structure. The formula of solid is `:`
A
`AB`
B
`AB_(2)`
C
`A_(2)B`
D
`A_(3)B_(4)`
Text Solution
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The correct Answer is:
a
In a closed packed structure, the number of tetrahedral voids per atom of the crystal is two. Since half of the tetrahedral voids are occupied by `A^(+)` , the number of `A^(+)` is same as that of `B^(-)` in the crystal . Thus formula is `AB`.
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