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The radius of the Na^(2+) is 95p m and t...

The radius of the `Na^(2+)` is `95p m` and that of `Cl^(-)` ion is `181 p m`. Predict the co`-` ordination number of `Na^(+) :`

A

4

B

6

C

8

D

unpredictable

Text Solution

Verified by Experts

The correct Answer is:
B
`(r_(Na^(+)))/(r_(Cl^(-)))=(95)/(181)=0.524, i.e., ` between `0.414` to `0.732` and thus co`-` ordination no. `=6`
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