A metal crystallises in `b.c.c.` lattice. The per cent fraction of edge length not covered by atom is `:`
A
`11.4%`
B
`12.4%`
C
`13.4%`
D
`14.4%`
Text Solution
Verified by Experts
The correct Answer is:
c
In `b.c.c.,` radius of atom `r=(sqrt(3)a)/(4` Also, edge length of unit cell `=a` `:. ` Edge length not covered by atom `=a-2r` `=a-(sqrt(3))/(2).a` `=a((2-sqrt(3))/(2))` `:. %` fraction not covered `(a((2-sqrt(3))/(2)))/(a)xx100=13.4%`
Topper's Solved these Questions
SOLID STATE
P BAHADUR|Exercise Exercise 9|1 Videos
MOCK TEST PAPER
P BAHADUR|Exercise Exercise|92 Videos
SURFACE CHEMISTRY
P BAHADUR|Exercise Exercise 5|1 Videos
Similar Questions
Explore conceptually related problems
A metal crystallizes in bcc lattice. The percent fraction of edge length not covered by atom is
A metal crystallises in bcc. Find % fraction of edge length not covered and also % fraction of edge length covered by atom is
In an atomic bcc lattie what fraction of edge is not covered by atoms?
If an atom crystallizes in bcc lattice with r=4 Å then the edge length will be
A metal crystallises in a bcc lattice ,its unit cell edge length in about 300 pm and its molar mass is about 50g mol^(-1) what would be the density of the metal (in g cm^(-3)) ?
What will be the percent fraction of edge length not covered by atoms when a metal crystallises in bcc lattice?
Suppose the mass of a single Ag atoms is 'm' Ag metal crystallises in fcc lattice with unit cell edge length 'a' The density of Ag metal in terms of 'a' and 'm' is:
