In the fcc arrangement of `A` and `B` atoms whose `A` atoms are at corners of the unit cell and `B` are at the face centres one of the `A` atom is missing from one corner in each unit cell. What is the simplest formula of the compound?
A
`A_(7)B_(3)`
B
`AB_(3)`
C
`A_(7)B_(24)`
D
`A_(7//8)B_(3)`
Text Solution
Verified by Experts
The correct Answer is:
c
No. of atoms of `A` from corners of unit cell `=(7)/(8)` No. atoms of `B` from faces of unit cell `=3` Thus `A:B::(7)/(8):3` or `7:24` Thus formula is `A_(7)B_(24)` Thus formula is `A_(7)B_(24)`.
Topper's Solved these Questions
SOLID STATE
P BAHADUR|Exercise Exercise 9|1 Videos
MOCK TEST PAPER
P BAHADUR|Exercise Exercise|92 Videos
SURFACE CHEMISTRY
P BAHADUR|Exercise Exercise 5|1 Videos
Similar Questions
Explore conceptually related problems
In a face centred cubic arrangement of A and B atoms whose A atoms are at the corner of the unit cell and B atoms at the face centres. Once of the A atom is missing from one corner in unit cell. The simplest formula of compound is
In a f.c.c. arrangement of A and B atoms, where A atoms are at the corners of the unit cell and B atoms at the face - centres, one of the A atom is missing from one corner in each unit cell. The formula of compound is :
In a face centered cubic arrangement of A and B atoms whose A atoms are at the corner of the unit cell and B atoms at the face centers. One of the B atoms missing from one of the face in unit cell. The simplest formula of compounding is:
In a fcc arrangement of A and B atoms, where A atoms are at the Corners of the unit cell, B atoms at the face centers, two atoms are missing from two corners in each unit cell, then the simplest formula of the compound is
In fcc arrangement of A and B atoms, where A atoms are at corners of the unit cell, B atoms at the face - centers, one of the atoms are missing from the corner in each unit cell then find the percentage of void space in the unit cell.
