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Two ionic solid AB and CB crystallise in...

Two ionic solid `AB` and `CB` crystallise in the same lattice. If `r_(A^(+))//r_(B^(-))` and `r_(C^(+))//r_(B^(-))` are `0.50` and `0.70` respectively, then the ratio of edge length of `AB` and `CB` is `:`

A

`0.88`

B

`0.78`

C

`0.68`

D

`0.58`

Text Solution

Verified by Experts

The correct Answer is:
a
`(r_(A^(+)))/(r_(B^(-)))=0.50` and `(r_(C^(+)))/(r_(B^(-)))`
`:. (r_(A^(+))+r_(B^(-)))/(r_(B^(-)))=1+0.50=1.50`
and `(r_(C^(+))+r^(B^(-)))/(r^(B-))=1+0.70=1.70`
`:. (r_(A^(+))+r_(B^(-)))/(r_(C^(+))+r_(B^(-)))=(1.50)/(1.70)`
`:' a_(AB)=2(r_(A^(+))+r_(B^(-)),a_(BC)=2(r_(C^(+))+r_(B^(-)))`
`(a_(AB))/(a_(CB))=(1.50)/(1.70)=0.88`
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