CsBr crystallises in a body centred cubic lattice. The unit cell length is 436 pm. Given that the atomic mass of Cs = 133 and that of Br = 80 amu and Avagadro number being `6.02xx10^(23)mol^(-1)` the density of CsBr is
A
`8.5g//cm^(3)`
B
`4.25g//cm^(3)`
C
`42.5g//cm^(3)`
D
`0.425g//cm^(3)`
Text Solution
Verified by Experts
The correct Answer is:
a
Density `=(zxxM)/(a^(3)xxN_(A))` `( :' z=2` for `b.c.c.` and `M_(CsBr)=213)` `=(2xx213)/((4.366xx10^(-8))^(3)xx6.023xx10^(23))` `=8.50g//cm^(3)`
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