The mole fraction of Schottky defect and Frenkel defects, in `NaCl` crystal at `1000K` are respectively. If energy required to produce these defects are `2eV` and `3eV` respectively. `(1eV=1.6xx10^(-19)J` and `k=1.38xx10^(-23)JK^(-1))`
A
`3.62xx10^(-7)` and `6.32xx10^(-9))`
B
`9.17xx10^(-6)` and `3.924xx10^(-8)`
C
`2.86xx10^(-5)` and `5.38xx10^(-8)`
D
`5.40xx10^(-8)` and `8.31xx10^(-9)`
Text Solution
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The correct Answer is:
b
Let the no. of Schottky defect be `n` in an ioinic crystal having `N` ions. `(n)/(N)=e^(-E//2kT)` `e^(((2xx1.6xx10^(-19))/(2xx1.38xx10^(-23)xx1000)))` `e^(-11.6)=9.17xx10^(-6)` Suppose the no. of Frenkel defects be `n` in an ionic crystal having `N` ions and interstitial space `N_((i))`. `n=sqrt(NxxN_((i)))e^(-E//2kT)` `( :' N_((i))=2N)` `:. n=sqrt(2)Ne^(-E//2kT)` `:. (n)/(N)=sqrt(2)e^(((3xx1.6xx10^(-19))/(2xx1.38xx10^(-23)xx1000)))` or `=sqrt(2)e^(-17.4)=3.924xx10^(-8)`
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