If radius of anion is `0.20nm`, the maximum radius of cations which can be filled in respective voids are correctly matched in `:`
A
`r^(+)=0.045nm` triangular void
B
`r^(+)=0.0828nm` for tetrahedral void
C
`r^(+)=0.1464nm` for octahedral voids
D
none of these
Text Solution
Verified by Experts
The correct Answer is:
a,b,c
`(r^(+))/(r^(-))` maximum for triangular, tetrahedral and octahedral are `0.225,0.414` and `0.732` respectively.
Topper's Solved these Questions
SOLID STATE
P BAHADUR|Exercise Exercise 9|1 Videos
MOCK TEST PAPER
P BAHADUR|Exercise Exercise|92 Videos
SURFACE CHEMISTRY
P BAHADUR|Exercise Exercise 5|1 Videos
Similar Questions
Explore conceptually related problems
If the radius of anion is 0.20 nm , the maximum radius of cation which can be filleed in respective voids is correctly matched in
For the closest packing of atoms A (radius, r_(A) ), the maximum radius of atom B that can be fitted into octahedral void is
A metal crystallizes in fcc arrangement with edge length equal to 400 nm. Calculate maximum possible radius of the atom which can fit in the voids without disturbing the crystal structure?
If in a solid AB of NaCl type radius of cation A^(+) is 50 pm ,then the maximum radius of anion B^(-) will be