The density of `Cr` atoms is `7.02g//cm`. If the unit cell has edge length `289p m`. Calculate the number of chromium atoms per unit cell. `(at ` masss of `Cr=52)`.
Text Solution
Verified by Experts
The correct Answer is:
2
Density `rho=(zxxat. wt.)/(a^(3)xxN_(A))` `z=(rhoxxa^(3)xxN_(A))/(at.wt.)` `=(7.2xx(289xx10^(-10))^(3)xx6.023xx10^(23))/(52)` `:. n=2`
Topper's Solved these Questions
SOLID STATE
P BAHADUR|Exercise Exercise 9|1 Videos
MOCK TEST PAPER
P BAHADUR|Exercise Exercise|92 Videos
SURFACE CHEMISTRY
P BAHADUR|Exercise Exercise 5|1 Videos
Similar Questions
Explore conceptually related problems
The number of atoms per unit cell in bcc lattice is
The density of chormium is 7.2"g cm"^(-3) . If the unit cell is a cube edge length of 298 pm, determine the type of the unit cell. (Atomic mass of Cr = 52 amu)
The number of carbon atoms per unit cell of diamond unit cell is
The number of carbon atoms per unit cell of diamond unit cell is
The density of KBr is 2.73g//cm . The length of the unit cell is 654p m . Find the number of atoms per unit cell in the cubic structure.
If the total number of atoms per unit cell is 2, the unit cell is
Calculate the number of atoms per unit cell present in simple, fcc and bcc unit cells.
