In `CsCl` with cubic structure, `Cl^(-)` ions are located at each corner and `Cs^(+)` ions at the centre of the unit cell. If `r_(Cs^(+))` and `r_(Cl^(-))` and `1.69Å` and `1.81Å` respectively. Find the value of edge length of cube.
If ionic radic radii of Cs^(+) and Ce^(-) are 1.69Å and 181Å respectively, the edge length of unit cell is
CsCl crystallizes in a cubic lattice and has a Cl^(-) at each corner and Cs^(+) at the centre of unit cell. If r_(Cs^(+))=1.69 Å and r_(Cl^(-))=1.81 Å , what is the value of edge - length 'a' of the cube ? Compare this values of 'a' (calculated) from the observed density of CsCl. 3.97 gm//cm^(3). [M_((CsCl))=168.5]
If the length of the body for CaCl which crystallizes into a cubic strructure with Cl^(Θ) ions at the corners and Cs^(o+) ions at the centre of the unit cell is 7 Å and the radius of he Cs^(o+) ions is 1.69Å , what is the radius of Cl^(ɵ) ions?
CsCl has bcc structure with Cs^(+) at the centre and Cl^(-) ion at each corner. If r_(Cs^(+)) is 1.69Å and r_(Cl^(-)) is 1.81Å what is the edge length of the cube?
The radii of Na^+ and Cl^- ions are 95 pm and 181 pm respectively. The edge length of NaCl unit cell is
In the zinc blende structure, zinc ions occupy alternate tetrahedral voids and S^(2-) ions exist as ccp the radii of Zn^(2+) and S^(2-) ions are 0.83Å and 1.74 Å respectively.The edge length of the ZnS unit cell is :
