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Temperature of 1mol of a gas is increase...

Temperature of `1mol` of a gas is increased by `1^(@)` at constant pressure. The work done is

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The correct Answer is:
2
At temperature `T, PV=RT`
Let the volume increase by `DeltaV`, when temperature is increased by `1^(@)`, at constant pressure,
`:. P(V+DeltaV)=R(T+1)`
`or PV+PDeltaV=RT+R`
`:' PV=RT`
`:. PDeltaV=R`
`:. `Work done `=R=2 cal`
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