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A solid made up of ions of A and B posse...

A solid made up of ions of `A` and `B` possess edge length of unit cell of `0.5664nm` has four formula units. Among the two ions, the smaller one occupy the interstitial void and the larger ions occupy the space lattice with ccp type of arrangement. One molecule of solid has mass `9.712xx10^(-23)g.`
The ionic radius of `B` ion assuming anion`-` anion contact is `:`

A

`1.815Å`

B

`1.994Å`

C

`1.682Å`

D

`1.712Å`

Text Solution

Verified by Experts

The correct Answer is:
b
`d_(A-B)=(5.64xx10^(-8)cm)/(2) =(5.64)/(2)Å`
`=2.82Å`

`:.d_(B-B)=sqrt((2.82)^(2)+(2.82)^(2))=3.988Å`
`:. r_(B)=(3.988)/(2)=1.994Å`
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