In a close packed structure of an ionic compound anions `B` form the close packed lattice and the cations `A` occupy octahedral voids.Predict the formula of the compound.
Text Solution
Verified by Experts
The correct Answer is:
`AB;`
Topper's Solved these Questions
SOLID STATE
P BAHADUR|Exercise Exercise 9|1 Videos
MOCK TEST PAPER
P BAHADUR|Exercise Exercise|92 Videos
SURFACE CHEMISTRY
P BAHADUR|Exercise Exercise 5|1 Videos
Similar Questions
Explore conceptually related problems
In a crystal of an ionic compound, the ions B form the close packed lattice and the ions A occupy all the tetrahedral voids. The formulaa of the compound is
In a crystal of an ionic compound, the anions B form a close packed lattice and the ions A occupy all the tetrahedral voiods. What is the formula of the compound ?
In a crystal of an ionic compound, the anions B form a close packed lattice and the cations A occupy one half of the tetrahedral voids. What is the formula of the compound ?
A compound is compound by cation C and anion A. The anions hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is
If the anions (A) form hexagonal closest packing and cations (C) occupy only 2/3 octahedral voids in it. Then the general formula of the compound is
If the anions (A) form hexagonal closest packing and cations (C ) occupy only 2/3 octahedral volids in it, then the general formula of the compound is: