In a crystal of an ionic compound, the anions `B` form a close packed lattice and the ions `A` occupy all the tetrahedral voiods. What is the formula of the compound ?
Text Solution
Verified by Experts
The correct Answer is:
`A_(2)B;`
Topper's Solved these Questions
SOLID STATE
P BAHADUR|Exercise Exercise 9|1 Videos
MOCK TEST PAPER
P BAHADUR|Exercise Exercise|92 Videos
SURFACE CHEMISTRY
P BAHADUR|Exercise Exercise 5|1 Videos
Similar Questions
Explore conceptually related problems
In a crystal of an ionic compound, the anions B form a close packed lattice and the cations A occupy one half of the tetrahedral voids. What is the formula of the compound ?
In a crystal of an ionic compound, the ions B form the close packed lattice and the ions A occupy all the tetrahedral voids. The formulaa of the compound is
In a close packed structure of an ionic compound anions B form the close packed lattice and the cations A occupy octahedral voids.Predict the formula of the compound.
A compound is compound by cation C and anion A. The anions hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is
Atoms of an element Z form hexagonal closed pack (hcp) lattice and atoms of element X occupy all the tetrahedral voids. The formula of the compound is
A compound is formed by two elements P and Q. Atoms of Q (as anions) make hcp lattice and those of the element P (as cations) occupy all the tetrahedral voids. What is the formula of the compound?
The anions A from hexagonal close packing and atoms (M) occupy only two-third of the octahedral voids. The general formula of the compound is
